How does Timer get_time_left() works?

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Serhy

func _input(event):
	if event.is_action_released("forward"):
		if (not $AccTimer.get_time_left() == 0):
			print('$AccTimer')
		else:
			print('hi')
			$AccTimer.start()

this code doesn't work properly
First it enters in second logic and print "hi" Then
no matter how many time elapse Its
always enters in first logic and print '$AccTimer'
I set Timer to "1" to "0.3" ...

DaveTheCoder

Serhy if (not $AccTimer.get_time_left() == 0):

Since time_left is a float, that should be:
if $AccTimer.time_left > 0.0:

Equality tests (==, !=) on floats are usually not reliable.

AspireMint

Serhy
Don't forget 2 important lines:

$AccTimer.one_shot = true
add_child($AccTimer)

then start your timer$AccTimer.start()

EDIT:
oh, timer is already in node tree, so just add this line before you start timer:
$AccTimer.one_shot = true

Serhy

DaveTheCoder the same thing

func _input(event):
	if event.is_action_released("forward"):
		if ($AccTimer.time_left > 0.0):
			print($AccTimer.time_left )
		else:
			print('hi')
			$AccTimer.start()

its like after Timer starts It
never goes zero
'Null
Null
hi
Null
Null
Null
Null
0.116667
Null
Null
0.283333
Null
Null
Null
0.283333
Null
Null
'
autorestarting?

Serhy

AspireMint just swa it So I checked
in the script I got error "$' unaxpected syntsx ... something I dont remember
and 'add_child($AccTimer) ' either
i found 'One shot' check box in the inspector and just enabled it
works Thanks

AspireMint

Serhy
Yes, sorry, my bad. I edited it. I was testing it with Timer.new() thats why I had to manually append it to node tree. But you already have instance of timer in node tree, so no need to add_child.